Question

Prosze o obliczenie :)

liczby algebraiczne

3a6b2ac=

¼*16x8y=

8a+9-10a-7=

4a-15+9a+30=

6b+4a-8b-6a+3b=

(4a+8b):(-2)=

(3+2x)*4+6*(3-5x)=

(8x+6y+10)*½+(2x-3y+4)*4=



LEGENDA

*=razy :)

Answer 1

3a6b2ac=36a²bc

¼*16x8y=4x*8y=32xy

8a+9-10a-7=-2a+2

4a-15+9a+30=13a-15

6b+4a-8b-6a+3b=b-2a

(4a+8b):(-2)=-2a-4b

(3+2x)*4+6*(3-5x)=12+8x+18-30x=-22x+30

(8x+6y+10)*½+(2x-3y+4)*4=4x+3y+5+8x-12y+16=12x-9y+21