Question

Prosze o obliczenie :)

liczby algebraiczne

3a6b2ac=

¼*16x8y=

8a+9-10a-7=

4a-15+9a+30=

6b+4a-8b-6a+3b=

(4a+8b):(-2)=

(3+2x)*4+6*(3-5x)=

(8x+6y+10)*½+(2x-3y+4)*4=



LEGENDA

*=razy :)

Answer 1

36a2bc
te dwa to do kwadratu
a+2
13a-15
b-2a
-8a-16b
12+8x+18-30x=30-22x
tego drugiego i ostatniego nie wiem

Answer 2

3a6b2ac = 6a6bc
1/4 * 16 x 8y =4.00x2.00y
8a+9-10a-7 =8a-10=-2a+9=7-7= 0
4a-15+9a+30 = 4a-9a=-5-15+30= -20+30=10
6b+4a-8b-6a+3b=6b-8b+3b=1b+10a
(4a+8b):(-2)=(-2a)+-(4b)
(3+2x)*4+6*(3-5x)=12+8x+18+30x=12+18=30+30xdo potęgi 2
(8x+6y+10)*1/2+(2x-3y+4)*4=4x+3y+5+2x-3y+4=4x+2x=6x+3y-3y=6x+9


proszę :)