prosze musze zdać na 4 !!!!!! Musze się dostać do technikum
V <- to jest znak pierwiastka
a) 3(x^2+2x+1) = x^2-2x+1+2x^2-V12x+V12x-6
3x^2+6x+3 = 3x^2-2x-5
8x = -5-3
8x =-8 /:8
x = -1
b) to równanie razy 4
4x-(x-2)(x+2) = 8-4(1/2x-3/2)^2
4x-(x^2-4) = 8-4(1/4x^2-2x+9/4)
4x-x^2+4 = 8-x^2+8x-9
4x = 5
x = 5/4 = 1 i 1/4
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V <- to jest znak pierwiastka
a) 3(x^2+2x+1) = x^2-2x+1+2x^2-V12x+V12x-6
3x^2+6x+3 = 3x^2-2x-5
8x = -5-3
8x =-8 /:8
x = -1
b) to równanie razy 4
4x-(x-2)(x+2) = 8-4(1/2x-3/2)^2
4x-(x^2-4) = 8-4(1/4x^2-2x+9/4)
4x-x^2+4 = 8-x^2+8x-9
4x = 5
x = 5/4 = 1 i 1/4