prosze musze zdać na 4 !!!!!! Musze się dostać do technikum
a) -3(5y-2)-1/2=-2(y+1/4) -15y+6-1/2=-2y-1/2
-13y+6=0
-13y=-6
-y=-2 i 1/13
y=2 i 1/13
b) 3x/4-x/2+7=(x+28)/4 /*4
3x-2x=28=x=28
0=0
c) t-(2t-1)/3=1/3(t-3) /*3
3t-2t-3=t-3
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a) -3(5y-2)-1/2=-2(y+1/4)
-15y+6-1/2=-2y-1/2
-13y+6=0
-13y=-6
-y=-2 i 1/13
y=2 i 1/13
b) 3x/4-x/2+7=(x+28)/4 /*4
3x-2x=28=x=28
0=0
c) t-(2t-1)/3=1/3(t-3) /*3
3t-2t-3=t-3
0=0