March 2019 0 5 Report
Proszę o szybką odpowiedz !!
prosze o wskazówki jak to rozwiazać
daje naj i duzo punktów !!a) \sqrt[3]{4}x = \sqrt[9]{-64}   \\ b) 2x + 3 = 6 \sqrt[3]{5}+x * \sqrt[3]{320} \\ c) 7 \sqrt[5]{-4} = -2 \sqrt[5]{128}x \\ d) 2x+ \sqrt{2} =1- \sqrt{2}x
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