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(x-2)² = 2*(x-2)*(x+1)
x² - 4x + 4 = 2 * (x² +x - 2x - 2)
x² - 4x + 4 = 2x² - 2x - 4
-x² - 2x + 8 = 0
Δ = 4 +32 = 36
√Δ = 6
x1 = 2
x2 = -4
2x-4=(2x-4)*(x+1)
(2x-4)*1=(2x-4)*(x+1) / :(2x-4)
1=x+1
x=0
Chyba że chodziło o (x-2)²=2*(x-2)*(x+1) to
x²-4x+4=(2x-4)*(x+1)
x²-4x+4=2x²+2x-4x-4
-x²-2x+8=0
Δ=4+32
Δ=36
x₁=(2-6):(-2)
x₁= 4/2 = 2
x₂=(2+6)/(-2)
x₂=8/(-2)
x₂=-4