Proszę o rozwiązanie zadania z góry dzięki :D
(x-2y)²-(x-2y)(x+2y)-4y(2y-1)=
=x²-4xy+4y²-x²+4y²-8y²+4y=
=4y-4xy=
---
x=1
y=13/257
=52/257 - 52/257=
=0
(x-2y)² - (x-2y)(x+2y) -4y(2y-1) =
= x²-4xy+4x²-(x²-4y²)-8y²+4y =
= x²-4xy+4y²-x²+4y²-8y²+4y =
= -4xy+4y =
= 4(y-xy)
dla x = 1 i y = 13/257
4(y-xy) = 4(13/257 - 1·13/257) = 4·0 = 0
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(x-2y)²-(x-2y)(x+2y)-4y(2y-1)=
=x²-4xy+4y²-x²+4y²-8y²+4y=
=4y-4xy=
---
x=1
y=13/257
---
=52/257 - 52/257=
=0
(x-2y)² - (x-2y)(x+2y) -4y(2y-1) =
= x²-4xy+4x²-(x²-4y²)-8y²+4y =
= x²-4xy+4y²-x²+4y²-8y²+4y =
= -4xy+4y =
= 4(y-xy)
dla x = 1 i y = 13/257
4(y-xy) = 4(13/257 - 1·13/257) = 4·0 = 0