Proszę o rozwiązanie tych równości logarytmów
Odp. C
Mamy
log 3 [2] * log 4 [3] * log 5 [4] *log 6 [ 5] =
= [ log 6 (2) / log 6 (3)] * [ log 6 (3) / log 6 (4)] * [ log 6 (4) / log 6 (5(] * log 6 (5) =
= log 6 ( 2)
===================
Korzystamy z wzoru na zamianę podstawy logarytmu:
log b (c) = log a ( c) / log a ( b )
============================
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Odp. C
Mamy
log 3 [2] * log 4 [3] * log 5 [4] *log 6 [ 5] =
= [ log 6 (2) / log 6 (3)] * [ log 6 (3) / log 6 (4)] * [ log 6 (4) / log 6 (5(] * log 6 (5) =
= log 6 ( 2)
===================
Korzystamy z wzoru na zamianę podstawy logarytmu:
log b (c) = log a ( c) / log a ( b )
============================