Proszę o rozwiązanie tych przykładów :D.... Question from @kodex13

monti444 B) 2/3 - [0,8 * 3/ $(-2)^{2}$ - $(-2)^{2}$ / 5] : (-1 1/2) =
= 2/3 - (0,8 * 3/4 - 4/5) : (-1 1/2) = 2/3 - (8/10 * 3/4 - 4/5) : (-1 1/2) =
= 2/3 - (2/10 * 3/1 - 4/5) : (-1 1/2 = 2/3 - (5/10 - 4/5) : (-1 1/2) =
= 2/3 - (5/10 - 8/10) : (-1 1/2) = 2/3 - (-3/10) * (-2/3) =
= 2/3 - 6/30 = 20/30 - 6/30 = 14/30 = 7/15

g) 4/5 : (1/2 - 1/5) - [2/3 - (3/8 - 1 1/3)] = 4/5 : (5/10 - 2/10) - {2/3 - (9/24 - 27/24) =
= 4/5 : 3/10 - (2/3 - (-18/24)) = 4/5 * 10/3 - (16/24 + 18/24) =
= 4/1 * 2/3 - 34/24 = 8/3 - 34/24 = 64/24 - 34/24 = 30/24 = 1 6/24 = 1 1/4

h) [(-1 1/2) $^{2}$ - (-1 1/3) $^{2}$ ] : 4 1/4 =
= [2,25 - 1,69] : 4 1/4 = 0,56 : 4 1/4 = 56/100 * 17/4 =
= 14/100 * 17/1 = 238/100 = 2 38/100 = 2 19/50 lub 2,38

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ema3153 B) $\frac{2}{3}-[0,8* \frac{3}{(-2)^2} - \frac{(-2)^2}{5} ]:( -1\frac{1}{2} )= \frac{2}{3}-[0,8* \frac{3}{4}- \frac{4}{5}]:( -\frac{3}{2} )= \frac{2}{3}-[ \frac{6}{10} -\frac{4}{5}]:( -\frac{3}{2} )=[\frac{2}{3}-(- \frac{2}{10} )]:( -\frac{3}{2} )=[\frac{2}{3}+\frac{2}{10}]:( -\frac{3}{2} )= \frac{26}{30} :( -\frac{3}{2} )= \frac{26}{30}*- \frac{2}{3}= -\frac{26}{45}$

g) $\frac{4}{5} :( \frac{1}{2}- \frac{1}{5}) -( \frac{2}{3}-( \frac{3}{8} -1 \frac{1}{3} ))= \frac{4}{5}:( \frac{5}{10} - \frac{2}{10} )-(\frac{2}{3}-( \frac{9}{24} -1 \frac{8}{24} )= \frac{4}{5}: \frac{3}{10} - (\frac{2}{3}-(- \frac{23}{24}))= \frac{4}{5}* \frac{10}{3}-( \frac{2}{3}+\frac{23}{24})= \frac{8}{3} -( \frac{16}{24} +\frac{23}{24})=\frac{8}{3}- \frac{39}{24} = \frac{64}{24} -\frac{39}{24}= \frac{25}{24}=1 \frac{1}{24}$
h) $((-1 \frac{1}{2} )^2-(-1 \frac{1}{3} )^2):4 \frac{1}{4} =((- \frac{3}{2})^2-(- \frac{4}{3})^2):4 \frac{1}{4}=(( \frac{9}{4})-( \frac{16}{9})): \frac{17}{4}=( \frac{81}{36}- \frac{64}{36}) :\frac{17}{4}= \frac{15}{36} :\frac{17}{4}=\frac{15}{36}* \frac{4}{17} = \frac{15}{153}$

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ema3153 tak w B zjadło mi wynik, ma być -26/45

kodex13 Wielkie Dzięki :D

ema3153 nie ma za co :P polecam się na przyszłość :P

Proszę o rozwiązanie tych zadań

Proszę o rozwiązanie tych zadań! Pilne !

jakie odczyny wyróżniamy jeżeli ph =4,7,8,10 to jaki jest odczyn?

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