Question

Proszę o rozwiązanie równań

Answer 1

Answer 2

A)
x⁴ - x³ - 6x² = 0
x²(x² - x - 6) = 0
x² = 0
x = 0
lub
x² - x - 6 = 0
Δ = 1 + 24 = 25
√Δ = 5
x₁ = (1-5)/2 = -2
x₂ = (1+5)/2 = 3

x = -2    v    x = 0      v    x = 3
x ∈ {-2; 0; 3} 


b)
x⁴ + 4x³ - 5x² = 0
x²(x² + 4x - 5) = 0
x² = 0
x = 0\lub
x² + 4x - 5 = 0
Δ = 16 + 20 = 36
√Δ = 6
x₁ = (-4-6)/2 = -5
x₂ = (-4+6)/2 = 1

x = -5    v    x = 0    v    x = 1
x ∈ {-5; 0; 1}