February 2019 0 11 Report
Proszę o rozwiązanie :-)
a) \frac{4}{x} = \frac{3}{2+x}
b) \frac{x}{x-1} = \frac{x+2}{x}
c)
 \frac{x+4}{2x-1} - \frac{1}{x} =0
d) \frac{2}{x+2} - \frac{1}{x-3} =0


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