Question

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log4(x+3)− log4 (x−1)= 2− log48

Answer 1

 

Answer 2

x + 3 > 0    i   x - 1 > 0

x > -3        i     x > 1

D:  x > 1

 

log4(x+3)− log4 (x−1)= 2− log4 8 

log4 [ (x+3) / (x−1) ] = log4 4^2 − log4 8

log4 [ (x+3) / (x−1) ] = log4 [ 4^2 / 8 ]

 (x+3) / (x−1) = 16 / 8

 (x+3) / (x−1) = 2 / 1

2(x - 1) = x + 3

2x - 2 = x + 3

2x - x = 3 + 2

x = 5   ------------  odpowiedx