Question

proszę o pomoc,z góry dzięki!

Answer 1

a) y=(x-4)² = x² - 8x + 16
b) -⅓(x-1)²+3 = -⅓ (x² - 2x + 1) + 3 = -⅓ x² + ⅔x -⅓  + 3 = -⅓ x² + ⅔x + 2⅔
c) √2(x-3)²-1 = √2(x² - 6x + 9) - 1 = √2x² -6√2x + 9√2 - 1
d) y=(-x-√2)²+2 = x² + x√2 + x√2 + 2 = x² + 2√2x + 2

 

Chyba tak:) 

 

to bylo do zadnia 1 

 

Zadanie drugie

 

 

a) y= x²-x-9

a=1, bo (1)*x²

b=-1, bo (-1)x

c=-9

Δ=1-4*1*(-9)=1+36=37

p= 1/2

q= -37/4= -9 i 1/4

 

y=(x-1/2)² - 9 i 1/4

 

b) y=x²-x+1/4

Δ= 1-4*1*1/4=0

p=1/2

q=0

 

y=(x-1/2)²

 

c) y=x²-5x+5

Δ=25-4*1*5=25-20=5

p=5/2

q= -5/4

 

y=(x-5/2)² - 5/4

 

d) y=x²-5x

Δ=25-4*1*0=25

p=5/2

q=-25/4

 

y=(x-5/2)²-25/4

 

e) y=x²+7x

Δ=49-4*1*0=49

p=-7/2

q=-49/4

 

y=(x+7/2)²-49/4

 

f)y=3x²-3x-1/4

Δ=9-4*3*(-1/4)=12

p=3/6=1/2

q=-12/12=-1

 

y=3(x-1/2)²-1

 

g)y=-2x²+4x+5

Δ=16-4*(-2)*5=56

p=-4/-4=1

q=-56/-8=7

 

y=-2(x-1)+7

 

h)y=4x²-12x+5

Δ=(-12)² - 4*4*5=64

p=12/8

q=-64/16

 

y=4(x-12/8)²-64/16

 

i)y=2x²+x+1

Δ=1-4*2*1=1-8=-7

p=-1/4

q=7/8

 

y=2(x+1/4)²+7/8