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A1, -3,15, A4 jest ciągiem geometrycznym. Znajdź iloraz tego ciągu oraz wyraz A1 i A4.
ciag geometryczny to taki, ze kojne wyrazy sa wieksze q razy.
wiec 15 = q * (-3) wiec q = 15/-3 = -5. (iloraz)
a1 = -3 / q = 3/5 = 0.6
a4 = 15 * q = -75
15 = q * (-3) wiec q = 15/-3 = -5. (iloraz)
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ciag geometryczny to taki, ze kojne wyrazy sa wieksze q razy.
wiec 15 = q * (-3) wiec q = 15/-3 = -5. (iloraz)
a1 = -3 / q = 3/5 = 0.6
a4 = 15 * q = -75
15 = q * (-3) wiec q = 15/-3 = -5. (iloraz)
a1 = -3 / q = 3/5 = 0.6
a4 = 15 * q = -75