promien okregu wpisanego w trojkat rownoboczny o dł 10cm ma dł ???
r=1:3h
h=(10 pierwaiastek z 3): 2
r=(5pierwiastek z 3) :3
a=10cm
r=aV3/6
r=10V3/6
r=5V3/3cm
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r=1:3h
h=(10 pierwaiastek z 3): 2
r=(5pierwiastek z 3) :3
a=10cm
r=aV3/6
r=10V3/6
r=5V3/3cm