Pb = 10 cm^2
zatem
h = p(10) cm
orqz
2 pi *r = p(10) ---> r = p(10)/( 2 pi)
Objętość walca
V = Pp * h = pi *r^2 * h = pi *[ p(10)/ (2 pi)]^2 * p(10) =
= pi* [ 10/4 pi^2] * p(10) = [ 5 p(10)]/( 2 pi )
Odp. V = [ 5 p(10)]/( 2 pI ) cm^3
================================
p(10) - pierwiastek kwadratowy z 10
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Pb = 10 cm^2
zatem
h = p(10) cm
orqz
2 pi *r = p(10) ---> r = p(10)/( 2 pi)
Objętość walca
V = Pp * h = pi *r^2 * h = pi *[ p(10)/ (2 pi)]^2 * p(10) =
= pi* [ 10/4 pi^2] * p(10) = [ 5 p(10)]/( 2 pi )
Odp. V = [ 5 p(10)]/( 2 pI ) cm^3
================================
p(10) - pierwiastek kwadratowy z 10