Potrzebuje rozwiazanie do logarytmow log(x+1)=1=log3-log6.... Question from @jenna1990

jenna1990 @jenna1990

November 2018 2 7 Report

Potrzebuje rozwiazanie do logarytmow log(x+1)=1=log3-log6

animaldk $log(x+1)=1+log3-log6\\\\D:x+1>0;\ x>-1\\\\x\in(-1;\infty)\\\\log(x+1)=log10+log3-log6\\\\log(x+1)=log(10\cdot3:6)\\\\log(x+1)=log5\\\\x+1=5\\\\x=5-1\\\\x=4\in D$

$Wzory:\\\\Dla\ a>0\ \wedge\ a\neq1\ \wedge\ b,c>0\\\\log_ab+log_ac=log_a(b\cdot c)\\\\log_ab-log_ac=log_a(b:c)\\\\log_aa=1\\\\log_ab=e\Leftrightarrow a^e=b\ dla\ e\in\mathbb{R}$

©DRK

0 votes Thanks 1

zuza0612 Log(x+1) = 1 + log 3 - log 6
log(x+1) = 1 + log 3/6
log(x+1) = 1 + log 1/2
log(x+1) = log 10 + log 1/2
log(x+1) = log 5

x + 1 = 5
x = 4

0 votes Thanks 1

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Pomylka tam ma byc log(x+1)=1+log3-log6

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