Question

Pomylka tam ma byc log(x+1)=1+log3-log6

Answer 1

log(x+1)=1+log3-log6                D:  x + 1 > 0
                                                                x > 1
log (x + 1) = log 10 + log 3/6
log (x + 1) = log (10 * 3/6)
log (x + 1) = log 5
x + 1 = 5
x = 4    nalezy do D
odp. x = 4