Question

Poproszę o pomoc!!
1.98

Answer 1

Log₂48-log₂3=log₂(48:3)=log₂16=log₂2⁴=4

log₃1/6+log₃2/3 = log₃(1/6*2/3)=log₃1/9=log₃3⁻² = -2

2log₁/₂√3+log₁/₂5¹/₃ = log₁/₂(√3²*16/3)=log₁/₂16=log₁/₂(1/2)⁻⁴=-4

log√2 50 - log√2 25 = log√2 (50:25) = log√2 (√2)² = 2

log₁/₃ 4+log₁/₃ 6 - log₁/₃ 8 = log₁/₃(4*6:8)=log₁/₃ 3 = log₁/₃3⁻¹=-1

log₁/₄8²-log√3 9³ = log₁/₄4³ - log√3 3⁶=3-log√3 (√3)¹²=3-12=-9