POOOOOOOMOCY!
Znajdź liczbę x jeżeli:
a) log₃ x = -3
b) log½(na dole) x = -2
c) log₀,₁ x = -1
d) log₁₆ x = -¼
definicja logarytmu
loga b = c -> a^c=b
a) 3⁻³=1/3³=1/27
b)(1/2)⁻²=(2/1)²=4
c)0,1⁻¹=(1/10)⁻¹=(10/1)¹=10
d)16^(-1/4)=1/⁴√16=1/2
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definicja logarytmu
loga b = c -> a^c=b
a) 3⁻³=1/3³=1/27
b)(1/2)⁻²=(2/1)²=4
c)0,1⁻¹=(1/10)⁻¹=(10/1)¹=10
d)16^(-1/4)=1/⁴√16=1/2