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masa NaOH = 40g/mol
masa Na2CO3 = 106g/mol
wg reakcji:
106g Na2CO3-------------2*40g NaOH
x g Na2CO3----------------30g NaOH
x = 39,75g Na2CO3
100%---------------x
83%---------------39,75g Na2CO3
x = 47,89g Na2CO3
2NaHCO3 -----> Na2CO3 + H2O + CO2
masa NaHCO3 = 84g
wg reakcji:
2*84g NaHCO3-----------106g Na2CO3
x g NaHCO3------------------47,89g Na2CO3
x = 75,90g NaHCO3
100%------------84g NaHCO3
x% -------------- 75,90g NaHCO3
x = 90,36%