Question

Pomocy !!!! klasa 6

Prezkształć w wyrażenia algebraiczne:

y+(2y-1)=

2(x+1)+1=

5y+5-(5-3y)+2y=

x+2(x+1)=

39y-1)+5=

3x-3(x-1)=

2(y+1)-y=

(x-2)-1=

2(y+1)+(y-1)=

(x+4)-1=

5(x+7)-5x=

+DAJE NAJ

Answer 1

y+(2y-1)= y+2y-1= 3y-1
2(x+1)+1=2x+2+1=2x+3
5y+5-(5-3y)+2y=5y+5-5+3y+2y=10y

x+2(x+1)=x+2x+2=3x+2

39y-1)+5=39y-1+5=39y-4

3x-3(x-1)=3x-3x+1=1

2(y+1)-y=2y+2-y=y+2

(x-2)-1=x-2-1=x-1

2(y+1)+(y-1)=2y+2+y-1=3y-1

(x+4)-1=x+4-1=x+3

5(x+7)-5x= 5x+35-5x=35

Proszę :) o to chodziło ? :)

Answer 2

y+(2y-1)= y + 2y - 1 = 3y - 1

 

2(x+1)+1= 2x + 2 + 1 = 2x + 3

 

5y+5-(5-3y)+2y= 5y + 5 - 5 + 3y + 2y = 10y

 

x+2(x+1)= x + 2x + 2 = 3x + 2

 

3(9y-1)+5= 27y - 3 + 5 = 27y + 2

 

3x-3(x-1)= 3x - 3x + 3 = 3

 

2(y+1)-y= 2y + 2 - y = y + 2

 

(x-2)-1= x - 2 - 1 = x - 3

 

2(y+1)+(y-1)= 2y + 2 + y - 1 = 3y + 1

 

(x+4)-1= x + 4 - 1 = x + 3

 

5(x+7)-5x= 5x + 35 - 5x = 35