Question

POMOCY DAJE NAJJ !!!

Na TERAZ!!!

Answer 1

(x+1)^3 = x^3 + 3*x^2*1 + 3*x*1^2 + 1^3 =

=x^3 + 3x^2  + 3x + 1

 

(x-1)^3 = x^3 - 3*x^2*1 + 3*x*1^2 -1^3=

=x^3 - 3x^2 + 3x -1

 

(x+3)^3= x^3 + 3*x^2*3 + 3*x*3^2 + 3^3=

=x^3 + 9x^2 + 27x +27

 

(x-4)^3 = x^3 - 3*x^2*4 + 3*x*4^2 - 4^3=

=x^3 - 12x^2 + 48x - 64

 

(2x+3)^3 = (2x)^3 + 3*(2x)^2*3+3*2x*3^2+3^3=

= 8x^3 + 36x^2 + 56x +27

(2x-1)^3 = (2x)^3 - 3*(2x)^2*1 -3*2x*1 - 1=

=8x^3 - 12x^2 + 6x -1

(3x+1)^3 = (3x)^3 + 3*(3x)^2*1 + 3*3x*1^3+1^3=

=27x^3 + 27x^2 + 9x +1

(1-3x)^3 = 1^3 - 3*1^2*3x + 3*1*(3x)^2 -(3x)^3=

=1 - 9x + 27x^2 - 27x^3

 

 

 

(a±b)^3 = a^3  ±  3a^b  +   3ab^2  ± b^3