Question

Pomocy!!

(3c+4d)*(3c+4d)+(4c-3d)*(4c-3d)=
(10-x)-(10+x)=
(5u-2w)(2w+5w)
2(x-y)(x+y)-3(2x-y)*(2x-y)
5(x-2)-(x-3)x+x(x-8)
-2x(3-x)-(2x*2x-6x+3)


Proszę o pomoc

Answer 1

(3c+4d)*(3c+4d)+(4c-3d)*(4c-3d)=9c²+12cd+12cd+16d²+16c²-12cd-12cd+9d²
=25c²+25d²

(10-x)-(10+x)=10-x-10-x=-2x

(5u-2w)(2w+5w)=10uw+25uw-4w²-10w²=35uw-14w²

2(x-y)(x+y)-3(2x-y)*(2x-y)=2(x²+xy-xy-y²)-3(4x²-2xy-2xy+y²)
=2(x²+y²)-3(4x²+y²)=2x²+2y²-12x²-3y²=-10x²-y²

5(x-2)-(x-3)x+x(x-8)=5x-10-x²+3x+x²+8x=16x-10

-2x(3-x)-(2x*2x-6x+3)=-6x+2x²-(4x²-6x+3)=-6x+2x-4x²+6x-3=2x-4x²-3