pomóżcie!
oblicz:
x = 27log32
log272 log272
log27x = log32 = ------------- = -------------- = 3log272 = log2723
log273 1/3
x = 23 = 8 czyli 27log32 = 8
27^log3 2 = (3^3)^log3 2 = 3^(3 * log3 2) = 3^log3 2^3 = 3^log3 8 = 8
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x = 27log32
log272 log272
log27x = log32 = ------------- = -------------- = 3log272 = log2723
log273 1/3
x = 23 = 8 czyli 27log32 = 8
27^log3 2 = (3^3)^log3 2 = 3^(3 * log3 2) = 3^log3 2^3 = 3^log3 8 = 8