pomóżcie!
a)
..... = [ 27^(1/2) ]^log3 2 = [ (3^3)^(1/2) ]^log3 2 = 3^(3/2)^log3 2 =
3^log3 2^(3/2) = 3^log3 √2³ = √8 = 2√2
... = 3^(log3 3 - log3 2) = 3^(log3 3/2) = 3/2
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..... = [ 27^(1/2) ]^log3 2 = [ (3^3)^(1/2) ]^log3 2 = 3^(3/2)^log3 2 =
3^log3 2^(3/2) = 3^log3 √2³ = √8 = 2√2
... = 3^(log3 3 - log3 2) = 3^(log3 3/2) = 3/2