pomoc wielomiany... mam problem z rozwiązaniem 2x4 + 4x3 - 5x2 = 0
2x⁴ + 4x³ - 5x² = 0
x²(2x²+4x - 5) = 0
x² = 0 lub 2x² + 4x - 5 = 0
x = 0
2x² +4x - 5 = 0
Δ = 4² -2*4*(-5) = 16 + 40 = 56
√Δ = √56 = √(4*14) = 2√14
x₁ = -4-2√14/2*2 = -1-0,5√14
x₂ = -4+2√14/2*2 = -1+0,5√14
Odp. x = 0 lub x = -1-0,5√14 lub x = -1+0,5√14
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2x⁴ + 4x³ - 5x² = 0
x²(2x²+4x - 5) = 0
x² = 0 lub 2x² + 4x - 5 = 0
x = 0
2x² +4x - 5 = 0
Δ = 4² -2*4*(-5) = 16 + 40 = 56
√Δ = √56 = √(4*14) = 2√14
x₁ = -4-2√14/2*2 = -1-0,5√14
x₂ = -4+2√14/2*2 = -1+0,5√14
Odp. x = 0 lub x = -1-0,5√14 lub x = -1+0,5√14
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Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)