Pole przekroju osiowego kuli jest rowne 12π. Oblicz objetosc tej kuli.
πr²=12π
r²=12
r=√12
v=4/3πr³=4/3π(√12)³=16π√12=32π√3 j.³
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πr²=12π
r²=12
r=√12
v=4/3πr³=4/3π(√12)³=16π√12=32π√3 j.³