Question

Obilcz ;
zad. 1
a) (46-4.25)+(23*4)+(456/16)=
b) (12*6,5)-(66*78-56,89)=
c) (34,456/68-9) * (34/73,678)=
d) (526-212)/ (32,89-11)=
e) (86,87*0,7-3)-(23*89)=
f) (31,92-82) * 111/ (935,567-54)=

zad. 2
a) (211-522)+(459*41*4+1)+(2655/18)=
b) (433*3,5)-(648*0,4)=
c)(456,35/32-78)*(627/3,675)=
d) (2324-235)/(2,3-21)=
e) (75,48 * 0,5-2) -(35*2-6)=
f) (412,5-2,5*5,4) / (456,13-1,2)=

LEGENDA ;
*- razy
/ -podzielić

Answer 1

Zad1
a (46 - 4.25) + (23 * 4) + (456 / 16) = 162.25
b (12 * 6,5) - ((66 * 78) - 56,89) = -5 013,11
c ((34 456 / 68) - 9) * (34 / 73 678) = 0.229675073
d (526 - 212) / (32,89 - 11) = 14,3444495
e ((86,87 * 0,7) - 3) - (23 * 89) = -1 989,191
f ((31,92 - 82) * 111) / (935,56700 - 54) = -6,30568068
zad 2

a(211 - 522) + ((459 * 41 * 4) + 1) + (2 655 / 18) = 75 113.5
b(433 * 3,5) - (648 * 0,4) = 1 256,3
c((456,35 / 32) - 78) * (627 / 3,67500) = -10 874,6645
d(2 324 - 235) / (2,3 - 21) = -111,71123
e((75,48 * 0,5) - 2) - ((35 * 2) - 6) = -28,26
f(412,5 - (2,5 * 5,4)) / (456,13 - 1,2) = 0,877058009

Answer 2

Zad 1
a) (46-4.25)+(23*4)+(456/16)= 41.75 +92 + 28.5 = 162.25

b) (12*6,5)-(66*78-56,89)= 78- 5091.11 = - 5013.11

c) (34,456/68-9) * (34/73,678)= 0,584 * 0,46 = 0,26864

d) (526-212)/ (32,89-11)= 314 / 21.89 = 14,34

e) (86,87*0,7-3)-(23*89)= 57,809 - 2047 = - 1989.191

f) (31,92-82) * 111/ (935,567-54)= -50.08 * 0,126 = -397.46

zad. 2
a) (211-522)+(459*41*4+1)+(2655/18)= -311 + 75277 +1475 = 75113.5

b) (433*3,5)-(648*0,4)=1515,5 - 259,2 = 1256,3

c)(456,35/32-78)*(627/3,675)= -11.78 * 170,61 = -2009.7858

d) (2324-235)/(2,3-21)=2089 / -18,7 = -111.71

e) (75,48 * 0,5-2) -(35*2-6)=35,74 - 64 = -28.26

f) (412,5-2,5*5,4) / (456,13-1,2)=399/ 454,93= 0,877