podstawy trapezu rownoramiennego maja dlguosc 11 cm i 27 cm a dlugosc ramiom wynosza 14cm jaka wysokosc ma ten trapez
(27-11):2=8
8²+h²=14²
64+h²=196
h²=196-64
h²=132
h=√132
h=2√33
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(27-11):2=8
8²+h²=14²
64+h²=196
h²=196-64
h²=132
h=√132
h=2√33