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Pp-pole podstawy
Pb-pole powierzchni bocznej
Pc=Pb+2×Pp
Pb=3×3×11
Pb=99 cm²
Pp=(a²√3)/4
Pp=(3²√3)/4
Pp=(9√3)/4
Pc=99+2×(9√3)/4
Pc=99+(9√3)/2 cm²