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założenia; 12x²≠0 x≠0
[-3x³+9x³] / 12x²=6x³ / 12x²=1/2 x
b]
założ.; -2x^5+3x^5≠0 x^5≠0 x≠0
[ (-3x²)²-8x^4] / x^5=(9x^4-8x^4) / x^5=x^4 / x^5=1/x
c]
załoz.5x≠0 x≠0
[-8x³+3x³] / 25x²= -5x³/25x²=-1/5 x
d]
załoz.18x^4-x³≠0 x³(18x-1)≠0 x≠0 i 18x≠1
x≠0 i x≠1/18
[x^6 * 9x²+9x³] / [ x³(18x-1)]=
[ 9x^8+9x³] /[ x³ (18x-1)]=
9x³(x^5+1) / x³(18x-1)=9(x^5+1) / ( 18x-1)