Podaj wartość funkcji sin²40°+sin²50°+sin²60.°
sin 50 = sin ( 90 - 40) = cos 40
zatem
sin ^2 40 + sin ^2 50 + sin ^2 60 =
= sin^2 40 + cos^2 40 + ( p(3)/2)^2 =
= 1 + 3/4 = 7/4
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sin 50 = sin ( 90 - 40) = cos 40
zatem
sin ^2 40 + sin ^2 50 + sin ^2 60 =
= sin^2 40 + cos^2 40 + ( p(3)/2)^2 =
= 1 + 3/4 = 7/4
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