Question

Plis yang jago kimia .. berserta jawabannya aku kasih yang terbaik

Answer 1

1.
diketahui =

C = 100 J/C derajad celcius
c =  4,2 J/gC derajad celcius

Delta T =  4 derajad celcius

massa total larutan = 150 + 100 = 250 gram

mol HCl = M x V
mol HCl = 0,1 x 0,3  = 0,03 mol

mol KOH = M x V
mol KOH = 0,2 x 0,15 = 0,03 mol

mol KCl = mol HCl = mol KOH = 0,03 mol

ditanyakan = Delta H ?
jawaban =.......

Kalor yang di lepaskan = Qair + Qbom
                                     =  m x c x DeltaT + C x Delta T
                                     = 250 x 4,2 x 4 + 100 x 4
                                     = 4600 J
                                     = 4,6 kJ


Delta H = -Q/molKCl
Delta H = -4,6 kJ/0,03
Delta H = 153,3333 kJ/mol


2.
diketahui =

massa gllukosa = 2,051 gram
Mr glukosa = 180
mol glukosa = massa / Mr = 2,051/180 = 0,01134 mol

massa air = 980 gram
c = 4,2 J/gC'
C = 8,2 J/C'
Delta T = 31,41 - 24,92
Delta T = 6,49 derajad celcius

ditanyakan = Delta H ...?
jawaban =

Kalor yang dilepaskan = Qair + Qbom
                                    = m x c x DeltaT + C x DeltaT
                                    = 980 x 4,2 x 6,49 + 8,2 x 6,49
                                    = 26.776 J
                                    = 26,776 kJ

Delta H = -Q/mol
Delta H = -26,776 kJ/0,1134
Delta H = -2.360 kJ/mol


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