Question

Please bantuin no 1-3 besok dikumpul!

Answer 1

1)
f(x) = 2x³ + (k-5) x² + (-8)x  - 4
f(2) = 20 --> 2(2³) +(k-5)(2²) + (-8)(2) - 4 = 20
16 + 4k - 20 -16 - 4 = 20
4k - 24 = 20
4k = 20+24 = 44
k = 11

2)  x - 1= 0 --> x = 1
f(1) = g(1)
1-4+5 +p = 1 +1- 2
2 + p = 0
p = -2

3) dibagi (x-13)(x-33) , sisa = S(x) = ax + b

s(13) = 33 --> 13 a + b = 33
s(33) = 13 --> 33a  + b = 13
kurangkan - 20 a = 20
a = -1
.
13a + b = 33 --> 13(-1) + b = 33
-13 + b = 33
b = 33 +13
b = 46

sisa pembagian s(x) = ax +b
atau s(x) = -(x) + 46
s(x) = 46 - x