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Verified answer
Jawaby = (x+1) sin (x² + 1)
y'= 1. sin (x²+1) + (x+1)(2x) cos (x²+1)
y' = sin(x² +1) + (2x² + 2x) cos (x²+1)
y" = 2x. cos (x²+1) + { (4x+2)(2x)(-sin (x²+1))
y" = 2x cos (x²+1) - (8x²+4x) sin (x²+1)