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1.) A₁ = 8 × 2 = 16
X₁ = 1
2.) A₂ = 4 × 2 = 8
X₂ = 2 + ( ¹/₂ × 2) = 4
3.) A₃ = 8 × 2 = 16
X₃ = 8 + ( ¹/₂ × 2) = 9
x = [A₁X₁ + A₂X₂ + A₃X₃]/ [A₁ + A₂ + A₃]
= [16.1 + 8.4 + 16.9]/ [16+ 8 + 16]
= [16 + 32 + 144]/ 40
x = 4,8
maka letak titik berat nya adalah (4,3)
Jawaban: D