Question

Please bantu saya ....

6 pangkat y-4 kali 2 pangkat y+2 dibagi 12 pangkat y-1 =

Answer 1

= [6^(y-4). 2^(y+2) ]/ (12^(y-1) =
= [ 6^(y-4). 2^(y+2) / ( 6^(y-1). 2^(y-1)
= 6 ^{ y-4 -y+1) . 2^(y+2 -y+1)
= 6^(-3). 2^(3)
=  2^-3. 3^-3. 2^3
= 3^-3
= 1/27