Question

Tolong saya, besok dikumpulin.....
(1/6)^2 kali akar 3 dari 6^2x + 1 =216

Answer 1

(1/6)² x ∛6^(2x+1) = 216
6^(-2) x 6^((2x+1)/3) = 6³
6^((-2)+((2x+1)/3)) = 6³
-2+ (2x+1)/3 = 3
-6 + 2x + 1 =9
2x = 9 +5
2x =14
x=7