proszę o szybkie rozwiązanie tego działania. Daję naj:)
(2/pierwiastek z 7 + 2/pierwiastek z 3) do potęgi 2=
(2/√7 + 2/√3)²=
(2/√7)²+(2*2/√7*2/√3)+(2/√3)²=
4/7+8/√21+4/3=
12/21+28/21+8/√21=40/21+8/√21=1 19/21+8/√21=
1 19/21+8√21/21=
1 19/21+8√21
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21
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(2/√7 + 2/√3)²=
(2/√7)²+(2*2/√7*2/√3)+(2/√3)²=
4/7+8/√21+4/3=
12/21+28/21+8/√21=40/21+8/√21=1 19/21+8/√21=
1 19/21+8√21/21=
1 19/21+8√21
____________
21