PH larutan yang terbentuk dari 10 mL CH3COOH 0,1 M dengan 10 mL Ba(OH)2 0,05 M menurut reaksi: 2CH3COOH + Ba(OH)2 = (CH3COOH)2Ba + 2H2O adalah.. (Ka: CH3COOH 10*pangkat*-5
bantu plis makasih!
nadhishafa
2 CH3COOH + Ba(OH)2 --> (CH3COOH)2Ba + 2 H2O m 2mmol 0,5mmol r 1mmol 0,5mmol 0,5mmol 1mmol s 1mmol 0,5mmol 1mmol
M= n/V = 0,5/20 = 0,025 [OH+] = = =
pOH = 6-log5 pH = 14 - (6-log5) = 8+log5
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hasbifadhilahs
Maaf tpi ko saya dpt jawaban dri kjnya 8,5 + log akar 5
m 2mmol 0,5mmol
r 1mmol 0,5mmol 0,5mmol 1mmol
s 1mmol 0,5mmol 1mmol
M= n/V = 0,5/20 = 0,025
[OH+] =
=
=
pOH = 6-log5
pH = 14 - (6-log5)
= 8+log5