Penyelesaian:
Pusat (2, 3) melalui titik (5, - 1)
(x - a)^2 + (y - b)^2 = r^2
(5 - 2)^2 + (- 1 - 3)^2 = r^2
9 + 16 = r^2
25 = r^2
Persamaan Lingkaran
(x - 2)^2 + (y - 3)^2 = 25
x^2 - 4x + 4 + y^2 - 6y + 9 = 25
x^2 + y^2 - 4x - 6y - 12 = 0
==================
Kelas: 11
Mapel: Matematika
Bab: Lingkaran
Kode: 11.2.5.1
Kata Kunci: Persamaan lingkaran, pusat, melalui titik
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Verified answer
Penyelesaian:
Pusat (2, 3) melalui titik (5, - 1)
(x - a)^2 + (y - b)^2 = r^2
(5 - 2)^2 + (- 1 - 3)^2 = r^2
9 + 16 = r^2
25 = r^2
Persamaan Lingkaran
(x - a)^2 + (y - b)^2 = r^2
(x - 2)^2 + (y - 3)^2 = 25
x^2 - 4x + 4 + y^2 - 6y + 9 = 25
x^2 + y^2 - 4x - 6y - 12 = 0
==================
Detil Jawaban
Kelas: 11
Mapel: Matematika
Bab: Lingkaran
Kode: 11.2.5.1
Kata Kunci: Persamaan lingkaran, pusat, melalui titik