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3a - b - 2 = 0 .... (i)
(x - a)² + (y - b)² = r²
Lingkaran melalui A(3,1) dan B(-1,3) maka
(3 - a)² + (1 - b)² = (-1 - a)² + (3 - b)² ....(ii)
Dari persamaan (i) dan (ii) diperoleh a = 2 dan b = 4.
r² = (3 - a)² + (1 - b)² = (3 - 2)² + (1 - 4)² = 10
Persamaan lingkaran:
(x - a)² + (y - b)² = r²
(x - 2)² + (y - 4)² = 10