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y1=-2
m=2
y-y1 = m(x-x1)
y-(-2)=2(x-(-3))
y+2=2(x+3)
y+2=2x+6
2x+6=y+2
2x-y=2-6
2x-y=-4
2x-y+4=0
jadi, persamaan garisnya adl b. 2x-y+4=0