Question

Persamaam lingkaran dengan pusat (1,-5) dan melalui titik (6.7) adalh.....

Answer 1

Verified answer

Kelas 11 Matematika
Bab Persamaan Lingkaran

(x - xp)² + (y - yp)² = r²
(6 - 1)² + (7 + 5)² = r²
25 + 144 = r²
r² = 169

(x - xp)² + (y - yp)² = r²
(x - 1)² + (y + 5)² = 169
x² - 2x + 1 + y² + 10y + 25 - 169 = 0
x² + y² - 2x + 10y - 143 = 0

Answer 2

Verified answer

(x,y)=(6,7)
(h,k)=(1,-5)
(x-h)²+(y-k)²=r²
(6-1)²+(7+5)²=r²
25+144=r²
169=r²
13=r

(x-h)²+(y-k)²=r²
(x-1)²+(y+5)²=169
x²+y²-2x+10y+26-169=0
x²+y²-2x+10y-143=0