Jawaban:
C
Penjelasan dengan langkah-langkah:
PYTHAGORAS
QS = 3 cm
PS : QS : PQ = √3 : 1 : 2
QS : PQ = 1 : 2
PQ = 2 × QS
PQ = 2 × 3
PQ = 6 cm
SR : QS : QR = 1 : √3 : 2
QS : QR = √3 : 2
QR = ⅔QS√3
QR = ⅔(3)√3
QR = 2√3 cm
PR² = PQ² + QR²
PR² = 6² + (2√3)²
PR² = 36 + 12
PR² = 48
PR = √48
tan <P = QS/PA
tan 30° = 3/PS
√3/3 = 3/PS
PS = 3 × 3/√3
PS = 9/√3
PS = 9√3 / 3
PS = 3√3 cm
tan <R = QS/RS
tan 60° = 3/RS
√3 = 3/RS
RS = 3/√3
RS = 3√3 / 3
RS = √3 cm
Maka:
PR
= PS + RS
= (3√3 + √3) cm
= 4√3 cm
Mapel: Matematika
Kelas: X
Materi: Bab 7 - Trigonometri
Kode Kategorisasi: 10.2.7
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Jawaban:
C
Penjelasan dengan langkah-langkah:
PYTHAGORAS
QS = 3 cm
PS : QS : PQ = √3 : 1 : 2
QS : PQ = 1 : 2
PQ = 2 × QS
PQ = 2 × 3
PQ = 6 cm
SR : QS : QR = 1 : √3 : 2
QS : QR = √3 : 2
QR = ⅔QS√3
QR = ⅔(3)√3
QR = 2√3 cm
PR² = PQ² + QR²
PR² = 6² + (2√3)²
PR² = 36 + 12
PR² = 48
PR = √48
PR = 4√3 cm ✔
Diketahui
Ditanya
Penyelesaian
tan <P = QS/PA
tan 30° = 3/PS
√3/3 = 3/PS
PS = 3 × 3/√3
PS = 9/√3
PS = 9√3 / 3
PS = 3√3 cm
tan <R = QS/RS
tan 60° = 3/RS
√3 = 3/RS
RS = 3/√3
RS = 3√3 / 3
RS = √3 cm
Maka:
PR
= PS + RS
= (3√3 + √3) cm
= 4√3 cm
_______________
DETAIL JAWABAN
Mapel: Matematika
Kelas: X
Materi: Bab 7 - Trigonometri
Kode Kategorisasi: 10.2.7