diket:
suhu 1 (T₁) = 27°C + 273 = 300 K
tekanan 1 (P₁) = 10⁵ atm
volume 1 (V₁) = 25 L
suhu 2 (T₂) = 100°C + 27°C = 127° + 273 K = 400 K
volume 2 (V₂) = 25 L - 5 L = 20 L
ditanya:
tekanan 2 (P₂)....?
jawab:
(10⁵ atm x 25 L) / 300 K = (P₂ x 20 L) / 400 K
(10⁵ x 25) / 3 = (P₂ x 20) / 4
--------------------------------------- bagi 5
(10⁵ x 5) / 3 = (P₂ x 4) / 4
P₂ = (10⁵ x 5) / 3
= 5/3 x 10⁵ atm
Jadi, besar tekanan gas oksigen sekarang adalah 5/3 x 10⁵ atm. (B)
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diket:
suhu 1 (T₁) = 27°C + 273 = 300 K
tekanan 1 (P₁) = 10⁵ atm
volume 1 (V₁) = 25 L
suhu 2 (T₂) = 100°C + 27°C = 127° + 273 K = 400 K
volume 2 (V₂) = 25 L - 5 L = 20 L
ditanya:
tekanan 2 (P₂)....?
jawab:
P₁ V₁ / T₁ = P₂ V₂ / T₂
(10⁵ atm x 25 L) / 300 K = (P₂ x 20 L) / 400 K
(10⁵ x 25) / 3 = (P₂ x 20) / 4
--------------------------------------- bagi 5
(10⁵ x 5) / 3 = (P₂ x 4) / 4
P₂ = (10⁵ x 5) / 3
= 5/3 x 10⁵ atm
Jadi, besar tekanan gas oksigen sekarang adalah 5/3 x 10⁵ atm. (B)