Question

Jika (3y-2) (y+5) = ay2+by+c, maka nilai a+b+c =
nb: itu ay kuadrat/pangkat dua bukan ay2

Answer 1

(3y-2)(y+5) = ay²+by+c
(3y-2)(y+5) = 3y²+15y-2y-10
                 = 3y²+13y-10
a = 3
b = 13
c = -10
a+b+c = 3+13-10
           = 6

Answer 2

(3y-2) (y+5) = 3y²+13y-10
a=3
b=13
c=-10
maka, a+b+c=3+13+(-10)=6