Zapisz w postaci sumy algebraicznej:
-3(2x+7)
-4(a-b)
7(-c)
-12(-1/3 +z)
a(a-b)
2a(3a-2)
-x(5y+x)
-2x(-2x-3+y)
(2x+6):2
3x-12):3
(4x-8):(-2)
(10x+15):5
/ oznacza kreske ułamkową
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-6x-21
-4a+4b
-7c
4-12z
a²-ab
6a²-4a
-5xy-x²
4x²+6x-2xy
x+3
x-4
-2x+4
2x+3
-3(2x+7)=-6x-21=-(6x+21)
-4(a-b)=-4a+4b
7(-c)=-7c+0
-12(-1/3 +z)=4-12z=-12z+4
a(a-b)=a^2-ab=-(-a^2+ab)
2a(3a-2)=6a^2-4a=-(-6a^2+4a)
-x(5y+x)=-5xy-x^2=-(5xy+x^2)
-2x(-2x-3+y)=4x^2+6x-2xy
(2x+6):2=x+3
3x-12):3=x-4=-(-x+4)
(4x-8):(-2)=-2x+4
(10x+15):5=2x+3