Question

Opuść nawiasy i zredukuj wyr. podobne .

a) (a-b)+[-(b-a)+b]=

b) (a+b-c)-[a+(a-b-c)]=

c) x+[-(y+x)+x-(y-1)]=

d) a- [b-(c+d)]-[(a+c)-(a-b)]=

e) (-a-b+c)-[-(a+b-c)+(-a-2b+c)]=

f) -[(x-y-z)-(-x+y+z)+(x+y-z)]=

g) (x+y+1)-[(-x+y)-(y+1)-(x-1)]=

h) (-x-y-3)+[-(x+y+1)-(x-y-3)]=

Potrzebuję tego na zaraz ! :P daje naj :*

Answer 1

a a-b+b-a+b=a-b+a

Answer 2

a)a-b-b+a+b

  2a-b

b)a+b-c-a-a+b+c

  -a+2b

c)x-y-x+x-y+1

  x-2y+1

d)a-b-c-d-a-c-a-b

  -a-2b-2c-d

e)-a-b+c+a-b+c-a-2b+c

  -a-4b+3c

f)-x+y+z+x-y-z+x+y-z

  x+y-z

g)x+y+1+x-y-y-1-x+1

  x-y+1

h)-x-y-3-x-y-1-x+y+3

  -3x-y-1